Escribe la función f(x) de la forma a(x –
h) + k y halle el vértice completando el cuadrado.
Ejemplos:
1.
f(x) = 2x2
+ 8x – 3
V = (-b/2a , f(-b/2a) )
2x2 + 8x – 3 = 0
2x2 + 8x = 3
2/2(x2 + 4x) = 3/2
x2 + 4x + (4/2)2 = 3/2 + (4/2)2
x2 + 4x + 4 = 3/2 + 4
√(x +2)2 = √11/2
x + 2 = +_ √11/2
x = 2 +- √11/2
f(x) = 2x2 + 8x -3
= (2x2 + 8x) – 3
= 2(x2 + 4x) – 3
= 2(x2 + 4x + 4) – 3
= 2(x2 + 4x + 4) – 3 – 8
f(x) = 2(x + 2)2 – 11
Vértice: (-2, -11)
V = (-b/2a , f(-b/2a) )
2x2 + 8x – 3 = 0
2x2 + 8x = 3
x2 + 4x + (4/2)2 = 3/2 + (4/2)2
x2 + 4x + 4 = 3/2 + 4
√(x +2)2 = √11/2
x + 2 = +_ √11/2
x = 2 +- √11/2
f(x) = 2x2 + 8x -3
= (2x2 + 8x) – 3
= 2(x2 + 4x) – 3
= 2(x2 + 4x + 4) – 3
= 2(x2 + 4x + 4) – 3 – 8
f(x) = 2(x + 2)2 – 11
Vértice: (-2, -11)
2.
f(x) = -5x2
– 9x + 10
= (-5x2 – 9x) + 10
= -5(x2 + 9/5x) + 10
= -5(x2 + 9/5x + 81/100 – 81/100) + 10
= -5(x2 + 9/5x + 81/100) + 10 + 405/100
= -5(x + 9/10)2 + 10 + 81/20
f(x) = -5(x + 9/10)2 + 281/20
Vértice: (-9/10, 281/20)
= (-5x2 – 9x) + 10
= -5(x2 + 9/5x) + 10
= -5(x2 + 9/5x + 81/100 – 81/100) + 10
= -5(x2 + 9/5x + 81/100) + 10 + 405/100
= -5(x + 9/10)2 + 10 + 81/20
f(x) = -5(x + 9/10)2 + 281/20
Vértice: (-9/10, 281/20)
3.
f(x) = -4x2
+ 16x – 2
= (-4x2 + 16x) – 2
= -4(x2 – 4x) – 2
= -4(x2 – 4x + 4 – 4) – 2
= -4(x2 – 4x + 4) – 2 +16
= -4(x – 2)2 + 14
Vértice: (2, 14)
= (-4x2 + 16x) – 2
= -4(x2 – 4x) – 2
= -4(x2 – 4x + 4 – 4) – 2
= -4(x2 – 4x + 4) – 2 +16
= -4(x – 2)2 + 14
Vértice: (2, 14)


















